Class 10 Physics Chapter 10 Test 1 – Thermal Physics | Punjab Board 2027

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10th Class Physics Chapter 10 Test 1 – Thermal Physics | Punjab Board 2027

Are you preparing for the 10th Class Physics Board Examination 2027? Get ready to improve your examination preparation with the Class 10 Physics Chapter 10 Test 1 – Thermal Physics, specially designed for students studying under the Punjab Boards. This chapter-wise Physics test is a useful practice resource for students who want to strengthen their understanding of Thermal Physics, revise important concepts, and prepare according to the Punjab Board examination pattern 2027. Visit 786Times.com to access educational resources, chapter-wise tests, model papers, and examination preparation material for Matric students.

📘 Class 10 Physics Chapter 10 Test 1 – Thermal Physics

The 10th Class Physics Chapter 10 Test 1 focuses on Thermal Physics, an important chapter in the Class 10 Physics syllabus. Students can use this test to check their understanding of the chapter and practise questions related to thermal concepts. Regular chapter-wise practice helps students improve their conceptual knowledge and prepare more effectively for school examinations and Punjab Board annual papers.

🎯 Thermal Physics Test – New Syllabus 2027

The Class 10 Thermal Physics Test 2027 is designed to support students in their preparation for the latest academic session. It provides an opportunity to revise the important topics of Chapter 10 and evaluate their learning through test-based practice. Students should carefully study their prescribed Physics textbook and attempt the chapter test to identify areas that require additional revision.

📚 Important Topics for Thermal Physics Preparation

While preparing for 10th Class Physics Chapter 10 Thermal Physics, students should focus on the concepts and exercises included in their prescribed textbook and syllabus. Understanding scientific concepts, learning important definitions, practising numerical problems where applicable, and revising relevant formulas can help students develop a strong foundation in Physics.

Benefits of Chapter-Wise Physics Tests

Improve understanding of Thermal Physics.
Practise important chapter-related questions.
Identify weak areas through self-assessment.
Improve examination preparation and confidence.
Develop better paper-solving and time-management skills.
Revise the chapter before school and board examinations.

📝 Punjab Board Class 10 Physics Test Series 2027

The Punjab Board 10th Class Physics Test Series 2027 is helpful for students who want to prepare chapter by chapter instead of studying the entire book at once. Chapter-wise Physics tests provide structured practice and help students monitor their progress throughout the academic session. Attempting different tests after completing each chapter can make final examination revision more organised and effective.

⬇️ Attempt Class 10 Physics Chapter 10 Test 1

Students can visit the following page to access the 10th Class Physics Chapter 10 Test 1 – Thermal Physics. Open the test, read the questions carefully, and attempt it to evaluate your preparation.

Physics Chapter 10 – Thermal Physics

Test 1 | Class 10 | Punjab Board 2027

📖 OPEN PHYSICS TEST 1

⭐ How to Prepare for the 10th Class Physics Examination 2027?

For better preparation, students should complete each Physics chapter according to the prescribed syllabus. Read the textbook carefully, understand the basic concepts, revise important definitions, and practise numerical questions. After completing Chapter 10, attempt the Thermal Physics chapter test and review your mistakes. Regular revision and consistent practice can help students improve their subject knowledge and perform confidently in the annual examination.

🌐 Get More Class 10 Educational Material at 786Times

786Times.com provides useful educational resources for students and teachers across Punjab, Pakistan. Students can explore Class 10 Physics Chapter-Wise Test Series 2027, Matric Model Papers 2027, Full Book Tests, Chapter-Wise Tests, Pairing Schemes, Smart Syllabus Updates, and Punjab Board Examination Preparation Material. Our aim is to make quality educational resources easily accessible to students preparing for their board examinations.

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A Educational Project in Pakistan

Prepare for the Punjab Board Matric Annual Examinations 2027 with Class 10 Physics Chapter 10: Thermal Physics – Class Test 1. This is a Board Standard Full Unit Test, specially designed to help students assess their understanding of Thermal Physics according to the latest Class 10 Physics New Syllabus issued by PECTAA Punjab. As part of our comprehensive Chapter-Wise Test Series, this practice paper supports effective exam preparation, concept revision, and self-assessment. Students can use this test to strengthen their knowledge of thermal physics and prepare confidently for the Punjab Boards 2027 examinations. In this test we covered following topics.

Textbook Topics No. (10.1-10.3),
Exercise S.Q (All),
Numerical No. (10.1-10.4),
Long Questions No. (10.1-10.2)

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Chapter Wise Class Test

T-1

Chapter-10

Thermal Physics

1.1 Choose the correct Answer.(Time: 7 Minutes)(Total Marks: 7)

If two rods of same length but different materials are heated equally, the rod that expands more has:

(a) Lower α(b) Higher density(c) Higher α(d) Lower temperature

Ans: (c) The expansion is ΔL = αL₀ΔT, so the rod with the higher coefficient of linear expansion (α) expands more.

If no space is left in railway tracks, they will:

(a) Shrink(b) Break(c) Melt(d) Buckle

Ans: (d) In hot weather the rails expand; with no gap they bend sideways (buckle).

If two substances receive equal heat and one shows smaller temperature rise, it has:

(a) Lower mass(b) Lower specific heat(c) Higher specific heat(d) Higher density

Ans: (c) Q = mcΔT; for the same Q, a smaller ΔT means a higher specific heat (c).

Metal feels colder than wood because:

(a) Metal is colder(b) Wood produces heat(c) Metal conducts heat away from our hand(d) Wood has lower temperature

Ans: (c) Metal is a good conductor, so it quickly takes heat away from the hand.

When the temperature of a rod of copper is increased, its length:

(a) remains the same(b) increases(c) decreases(d) becomes double

Ans: (b) Solids expand on heating, so the length increases.

The amount by which unit length of a material increases when the temperature is raised to 1°C, is called the coefficient of:

(a) cubic expansion(b) volume expansion(c) linear expansion(d) none of these

Ans: (c) This is the definition of the coefficient of linear expansion (α).

What does a liquid turn into once it is evaporated?

(a) Gas(b) Water vapours(c) Air(d) Both (a) and (b)

Ans: (d) An evaporated liquid becomes gas (vapour); water becomes water vapour.

Class 10 Physics | Chapter-10: Thermal Physics | Objective Type

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Chapter Wise Class Test

T-1

Chapter-10

Thermal Physics

Total Marks: 23(Subjective Type)Time: 33 Minutes

2.Write short answers to any Seven (7) questions.[7 × 2 = 14]

(i)

Why do bridges have expansion joints?

Bridges are made of steel and concrete, which expand in hot weather and contract in cold weather. Expansion joints leave gaps so the material can expand freely, which prevents cracking and buckling.

(ii)

Why does a metal lid open easily when heated?

When heated, the metal lid expands more than the glass jar because metals have a larger coefficient of expansion. The lid becomes loose and opens easily.

(iii)

Why is water used in automobile cooling systems?

Water has a high specific heat capacity (4200 J kg⁻¹ K⁻¹), so it absorbs a large amount of heat from the engine with only a small rise in temperature. It is also cheap and easily available.

(iv)

Why does soil heat up faster than water?

Soil has a lower specific heat than water. For the same amount of heat, the temperature of soil rises more than that of water, so soil heats up faster.

(v)

Why does metal feel colder than wood when touched, if they are both at the same temperature?

Metal is a good conductor of heat, so it quickly takes heat away from our hand and we feel cold. Wood is a poor conductor, so it takes away heat slowly and feels warmer.

(vi)

What is latent heat of fusion?

The heat energy required to change 1 kg of a solid into a liquid at its melting point, without any change in temperature, is called latent heat of fusion. L_f = Q / m (for ice, 3.36 × 10⁵ J/kg).

(vii)

How do different materials exhibit varying thermal expansion behaviours?

Each material has its own coefficient of linear expansion (α), so the change in length ΔL = αL₀ΔT is different for the same rise in temperature. For example, aluminium expands more than steel, and glass expands very little. This is used in a bimetallic strip.

(viii)

How does evaporation contribute to cooling processes in everyday life?

During evaporation, the fastest (most energetic) molecules escape from the liquid surface, so the average energy of the remaining liquid falls and it cools. Examples: sweating cools the body, water in an earthen pot stays cool, and wet cloth on the forehead reduces fever.

(ix)

What is latent heat of vaporization, and how is it calculated?

The heat energy required to change 1 kg of a liquid into vapour at its boiling point, without any change in temperature, is called latent heat of vaporization. L_v = Q / m, or Q = mL_v. For water, L_v = 2.26 × 10⁶ J/kg.

3.Give Answers of the following questions.[4 + 5 = 9]

(i)

What are some practical consequences of thermal expansion in everyday life, such as in construction materials or household appliances?

Railway tracks: gaps are left between rails so they do not buckle in summer.
Bridges and concrete roads: expansion joints allow free expansion and contraction.
Power lines: cables are hung slightly loose; they sag in summer and tighten in winter.
Appliances: a bimetallic strip in an electric iron, toaster or thermostat bends on heating and switches the circuit off.
Glass: a thick glass cracks if heated suddenly because it expands unevenly; metal lids are loosened by warming.

(ii)

A container holds 1 litre of water at 20°C. What will be its volume at 80°C, assuming water’s coefficient of volume expansion is 2.1×10⁻⁴ per °C?

Given: V₀ = 1 L, T₁ = 20°C, T₂ = 80°C, β = 2.1 × 10⁻⁴ °C⁻¹
ΔT = 80 − 20 = 60°C
ΔV = βV₀ΔT = 2.1 × 10⁻⁴ × 1 × 60 = 0.0126 L
V = V₀ + ΔV = 1 + 0.0126 = 1.0126 L (≈ 1012.6 cm³)

Class 10 Physics | Chapter-10: Thermal Physics | Subjective Type

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