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Class 10 Chemistry Chapter 21 Organic Chemistry Test 8

Class 10 Chemistry chapter 21 Model Paper Test 8

Prepare for the Punjab Board Class 10 Chemistry Examination 2027 with Chapter 21: Organic Chemistry – Class Test No. 8. This full chapter test, including textbook exercises, is designed to help students revise important concepts and practice exam-style questions according to the new Chemistry syllabus issued by PECTAA Punjab. As part of our Punjab Board 2027 Model Papers, Full Unit Model Papers, and Chapter-Wise Test Series, this test helps students evaluate their preparation, strengthen their understanding of Organic Chemistry, and improve their performance in the annual examination. Practice this Class 10 Chemistry Chapter 21 test to build confidence and prepare effectively for the 2027 board exams.

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PAPER NO.08
CHEMISTRY
Chapter
Wise
Roll No.(in Figures):
(in Words):
Chapter 21:
Organic Chemistry
Objective Type
Maximum Marks: 12
Time Allowed : 15 Minutes
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2ABCD
3ABCD
4ABCD
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5ABCD
6ABCD
7ABCD
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9ABCD
10ABCD
11ABCD
12ABCD
NOTE:Four possible answers A, B, C and D to each question are given. The choice which you think is correct, fill that circle in front of that question with Marker or Pen ink. Cutting or filling two or more circles will result in zero mark in that question.
Q1.12
1. Choose the correct IUPAC name for the compound HC||CH2 – CH – CH3
(A) But-3-ene
(B) But-1-ene
(C) But-2-ene
(D) Butene
Answer: B
2.Which of the following is NOT studied as organic compound?
(A) Hydrocarbons
(B) Alcohols
(C) Carbonates of carbon
(D) Carboxylic acids
Answer: C
3.Identify the aldehydic functional group among the following:
(A) –CO||–OH
(B) –CO||–
(C) – OH
(D) –CO||–H
Answer: D
4.The condensed structural formula of ethanol is:
(A) CH3-CH2
(B) CH2=CH2
(C) CH3-CH2-OH
(D) HC ≡ CH
Answer: C
5.Select the general formula of alkyne family.
(A) CnH2n+1
(B) CnH2n
(C) CnH2n-2
(D) CnH2n-1
Answer: C
6.The general formula for alkenes is:
(A) CnH3n
(B) CnH2n
(C) CnH4n
(D) CnHn
Answer: B
7.How many structural isomers will be there for a saturated hydrocarbon having five carbon atoms?
(A) 2
(B) 3
(C) 4
(D) 5
Answer: B (n-pentane, isopentane, neopentane)
8.The phenomenon of having same molecular formula but different structural formulae is called:
(A) Polymerization
(B) Homology
(C) Structural isomerism
(D) Condensation
Answer: C
9.Which ester among the following will be called ethylpropanoate?
(A) CH3 – CO|| – OCH3
(B) CH3 – CH2 – CO|| – OCH3
(C) CH3 – CO|| – OC2H5
(D) CH3 – CH2 – CO|| – OC2H5
Answer: D
10.When hydroxyl group (-OH) is attached to benzene ring, the compound belongs to:
(A) Alcohols
(B) Phenols
(C) Aldehydes
(D) Ketones
Answer: B
11.Which functional group is present in alkenes?
(A) No Functional group
(B) Carbon – carbon triple bond
(C) Carbon – carbon double bond
(D) Carbon-carbon single bond
Answer: C
12.The IUPAC name of CH3-CH2-CH2-OH is:
(A) Propan-2-ol
(B) Butan-1-ol
(C) Propan-1-ol
(D) Ethanol
Answer: C

Here is Subjective Part of Paper.

Roll No.(in Figures): (in Words):
Chapter 21:

Organic Chemistry

SUBJECTIVE TYPE

(PART – I)

Maximum Marks: 48

Time Allowed :1.45 Hours
Q2.Write short answers to any FIVE (5) questions:(5×2=10)
(i)
What is the difference between saturated and unsaturated hydrocarbons?

Saturated hydrocarbons: contain only single (C–C) bonds, e.g. alkanes (general formula CnH2n+2) such as ethane.

Unsaturated hydrocarbons: contain at least one double (C=C) or triple (C≡C) bond, e.g. alkenes (CnH2n) and alkynes (CnH2n−2) such as ethene and ethyne.

(ii)
Define organic chemistry.

Organic chemistry is the branch of chemistry that deals with the study of hydrocarbons and their derivatives, i.e. the compounds of carbon (except oxides of carbon, carbonates, bicarbonates, carbides, etc.).

(iii)
Write down the structural formula of Butan-2-ol.

Condensed formula: CH3–CH(OH)–CH2–CH3

    H   H   H   H
    │   │   │   │
H ─ C ─ C ─ C ─ C ─ H
    │   │   │   │
    H   O   H   H
        │
        H
Displayed formula of butan-2-ol
(iv)
How are organic compounds broadly classified?

Organic compounds are broadly classified into two main classes:

Organic compounds
├── Acyclic (open chain)
│   ├── Straight chain
│   └── Branched chain
└── Cyclic (closed chain)
    ├── Homocyclic (Carbocyclic)
    │   ├── Alicyclic
    │   └── Aromatic
    └── Heterocyclic
(v)
Why is ethylamine called an organic compound?

Ethylamine (C2H5NH2) is a derivative of the hydrocarbon ethane (C2H6) in which one hydrogen atom is replaced by the amino group (−NH2). It contains carbon and hydrogen bonded together, so it is an organic compound.

(vi)
What are carbocyclic compounds?

Carbocyclic (homocyclic) compounds are cyclic compounds whose ring is made up of carbon atoms only. They are of two types: alicyclic (e.g. cyclopropane, cyclohexane) and aromatic (e.g. benzene).

Cyclopropane
Cyclohexane
Benzene
(vii)
Write down the formula of an ester called ethyl methanoate.

Condensed formula: HCOOC2H5 or HCOOCH2CH3

    O       H   H
    ║       │   │
H ─ C ─ O ─ C ─ C ─ H
            │   │
            H   H
Displayed formula of ethyl methanoate
(viii)
What are alicyclic compounds?

Alicyclic compounds are carbocyclic compounds that contain a ring of carbon atoms but behave like aliphatic (open-chain) compounds. The ring may have single or multiple bonds, e.g. cyclopropane, cyclohexane and cyclohexene.

Cyclopropane
Cyclohexane
Cyclohexene
Q3.Write short answers to any FIVE (5) questions:(5×2=10)
(i)
Define structural isomerism.

The phenomenon in which two or more compounds have the same molecular formula but different structural formulae (different arrangement of atoms) is called structural isomerism. Example: butane and 2-methylpropane, both C4H10.

(ii)
What is a displayed formula or full structural formula?

A formula that shows all the atoms present in a molecule and all the covalent bonds between them (each bond drawn as a line) is called a displayed or full structural formula.

    H   H
    │   │
H ─ C ─ C ─ H
    │   │
    H   H
Ethane (C2H6)
(iii)
Give IUPAC name to CH3 – CH2 – CH2 – CH3

Butane (four carbon atoms in a straight chain, all single bonds).

(iv)
Write the displayed and condensed formulae of ethyne.
H ─ C ≡ C ─ H
Displayed formula
HC≡CH  (or  CH≡CH)
Condensed formula
(v)
What is common in carboxyl group, amide functional group and ester functional group?

All three contain the carbonyl group (C=O). In each, the carbonyl carbon is also bonded to another atom/group: −OH in carboxyl, −NH2 in amide and −OR in ester.

  O
  ║
─ C ─ O ─ H
Carboxyl
  O
  ║
─ C ─ N ─ H
        │
        H
Amide
  O
  ║
─ C ─ O ─ R
Ester
(vi)
Write the displayed and condensed formula of methyl ethanoate.

Condensed formula: CH3COOCH3

    H   O       H
    │   ║       │
H ─ C ─ C ─ O ─ C ─ H
    │           │
    H           H
Displayed formula of methyl ethanoate
(vii)
Why the members of a homologous series have similar chemical properties?

Because all members of a homologous series contain the same functional group, and the chemical properties of an organic compound are mainly determined by its functional group.

(viii)
What is the general formula of alkanes?

CnH2n+2 (where n = 1, 2, 3 …), e.g. CH4, C2H6, C3H8.

Q4.Write short answers to any FIVE (5) questions:(5×2=10)
(i)
How are the properties of 2–methyl propane different from n-butane, both containing the same number of carbon atoms?

Both have the formula C4H10 but different structures, so their physical properties differ. n-Butane is a straight chain with a larger surface area and stronger van der Waals forces, hence a higher boiling point (about −0.5 °C). 2-Methylpropane is branched and more compact, with weaker forces and a lower boiling point (about −11.7 °C). Their chemical properties are similar.

CH₃ ─ CH₂ ─ CH₂ ─ CH₃
n-Butane
      CH₃
       │
CH₃ ─ CH ─ CH₃
2-Methylpropane
(ii)
What are aromatic compounds?

Aromatic compounds are carbocyclic compounds that contain one or more benzene rings (a planar six-carbon ring with alternate single and double bonds), and usually have a characteristic smell. Examples: benzene (C6H6), toluene, phenol.

Benzene
(iii)
Write down the structural formulae of isomers shown by saturated hydrocarbon containing five carbon atoms.

Pentane, C5H12, shows three isomers:

CH₃ ─ CH₂ ─ CH₂ ─ CH₂ ─ CH₃
(1) n-Pentane
CH₃ ─ CH ─ CH₂ ─ CH₃
      │
      CH₃
(2) 2-Methylbutane
      CH₃
      │
CH₃ ─ C ─ CH₃
      │
      CH₃
(3) 2,2-Dimethylpropane
(iv)
Is structural isomerism confined to saturated hydrocarbons only?

No. Structural isomerism is also found in unsaturated hydrocarbons (e.g. butene: but-1-ene and but-2-ene) and in compounds with functional groups (e.g. ethanol CH3CH2OH and dimethyl ether CH3OCH3, both C2H6O).

(v)
Write down the structural formula of the isomers shown by butene.

Butene, C4H8:

CH₂ = CH ─ CH₂ ─ CH₃
(1) But-1-ene
CH₃ ─ CH = CH ─ CH₃
(2) But-2-ene
      CH₃
       │
CH₃ ─ C = CH₂
(3) 2-Methylpropene
(vi)
What are phenols and how are they different from alcohols?

Phenols are compounds in which the hydroxyl group (−OH) is attached directly to a carbon atom of a benzene (aromatic) ring, e.g. phenol C6H5OH. In alcohols, the −OH group is attached to a saturated carbon atom of an alkyl group, e.g. ethanol. Phenols are weakly acidic, while alcohols are neutral.

OHPhenol
CH₃ ─ CH₂ ─ OH
Ethanol (alcohol)
(vii)
Explain the difference among functional group present in aldehyde, ketone and carboxylic acid.
  • Aldehyde (−CHO): carbonyl carbon is bonded to at least one hydrogen; it lies at the end of the chain.
  • Ketone (>C=O): carbonyl carbon is bonded to two carbon atoms, within the chain.
  • Carboxylic acid (−COOH): carbonyl carbon is also bonded to a hydroxyl (−OH) group.
    O
    ║
R ─ C ─ H
Aldehyde
     O
     ║
R ─ C ─ R'
Ketone
    O
    ║
R ─ C ─ O ─ H
Carboxylic acid
(viii)
How are esters named according to IUPAC system?

An ester name has two words: the first is the alkyl group of the alcohol part, and the second is the alkanoate name from the acid part (replace “-oic acid” with “-oate”). Example: CH3COOCH3 = methyl ethanoate; HCOOC2H5 = ethyl methanoate.

(PART – II)
Note: Attempt any TWO questions.(2 × 9 = 18)
Q5.(a) What is an organic compound? How organic compounds are classified based on the type of carbon chain present in them?5

Organic compound: a compound of carbon that is a hydrocarbon or a derivative of a hydrocarbon (contains C–H bonds), e.g. methane, ethanol, ethanoic acid.

Classification (by type of carbon chain):

  1. Acyclic (open chain / aliphatic): carbon atoms form straight or branched chains with free ends.
  2. Cyclic (closed chain): carbon atoms form a ring.
    • Homocyclic (carbocyclic): ring contains carbon only – alicyclic (e.g. cyclohexane) and aromatic (e.g. benzene).
    • Heterocyclic: ring contains carbon and other atoms (N, O, S), e.g. pyridine, furan.
Organic compounds
├── Acyclic (open chain)
│   ├── Straight chain
│   └── Branched chain
└── Cyclic (closed chain)
    ├── Homocyclic (Carbocyclic)
    │   ├── Alicyclic
    │   └── Aromatic
    └── Heterocyclic
(b) Write down five characteristics of a homologous series.4
  1. All members have the same general formula (e.g. CnH2n+2 for alkanes).
  2. Two successive members differ by a CH2 unit (14 a.m.u.).
  3. All members contain the same functional group, so they have similar chemical properties.
  4. Physical properties (melting point, boiling point, density) change gradually with increasing molecular mass.
  5. Members can be prepared by similar general methods.
Q6.(a) Explain structural formula giving examples.5

A structural formula shows how the atoms of a molecule are arranged and bonded to each other. Main types: displayed (full) formula, showing every atom and bond, and condensed formula, showing atoms grouped without drawing all bonds.

    H   H
    │   │
H ─ C ─ C ─ O ─ H
    │   │
    H   H
Ethanol – displayed
CH₃CH₂OH
Ethanol – condensed
H       H
  ╲   ╱
   C = C
  ╱   ╲
H       H
Ethene – displayed
CH₂=CH₂
Ethene – condensed

Structural formulae also help to show isomers: C4H10 has two different structures (butane and 2-methylpropane).

(b) How systematic way of naming organic compounds was introduced?4

Earlier, organic compounds had common (trivial) names based on their source (e.g. formic acid from ants), which caused confusion as thousands of compounds were discovered. A systematic scheme was first proposed at the Geneva Congress (1892), and later developed and regularly revised by IUPAC (International Union of Pure and Applied Chemistry). An IUPAC name has three parts: prefix + word root + suffix.

Carbons123456
Word rootMethEthPropButPentHex

Suffixes: –ane, –ene, –yne (primary); –ol, –al, –one, –oic acid (functional group).

Q7.(a) Give IUPAC rules for naming alcohols.5
  1. Select the longest continuous carbon chain that contains the −OH group.
  2. Name the parent alkane and replace the last “e” with “ol” (ethane → ethanol).
  3. Number the chain from the end that gives the −OH group the lowest number.
  4. Write the position of −OH before “ol” (e.g. propan-2-ol); other substituents are named with their positions in alphabetical order as prefixes.
  5. For more than one −OH, keep the “e” and use di-, tri- (e.g. ethane-1,2-diol).
CH₃OH
Methanol
CH₃ ─ CH₂ ─ OH
Ethanol
CH₃ ─ CH ─ CH₃
      │
      OH
Propan-2-ol
(b) What are Carboxylic acids. How are they named by IUPAC system?4

Carboxylic acids are organic compounds containing the carboxyl group (−COOH); general formula R−COOH or CnH2n+1COOH.

IUPAC naming: select the longest chain including the carboxyl carbon, which is always C-1; replace the last “e” of the alkane with “oic acid”. Substituents are numbered from the carboxyl carbon.

FormulaIUPAC name
HCOOHMethanoic acid
CH3COOHEthanoic acid
CH3CH2COOHPropanoic acid
CH3CH(CH3)COOH2-Methylpropanoic acid
    O
    ║
R ─ C ─ O ─ H
Carboxyl group
© 786Times – Chapter 21: Organic Chemistry

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